Using `xsl:with-param` in invalid parent node

xsl:with-param passes a value to the template a call invokes, so it belongs only inside xsl:call-template, xsl:apply-templates, xsl:apply-imports, xsl:next-match, xsl:next-iteration, or xsl:evaluate. Anywhere else a processor refuses the whole module, and the stylesheet runs no transformation at all.

Incorrect:

<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
  <xsl:with-param name="Kipling" select="1865"/>
</xsl:stylesheet>

Correct:

<xsl:call-template name="myTemplate">
  <xsl:with-param name="Shakespeare" select="1564"/>
</xsl:call-template>

XSLT 1.0 defines xsl:apply-imports as empty, so a parameter inside one is reported where the version in force is below 2.0. Raise that version, or pass the value another way.

Using xsl:with-param in invalid parent node

Using `xsl:with-param` in invalid parent node